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x2 y2 6x 2y 10

(1)15x3y5次方(y-x)3分之12x2y(x-y)4次方 =12x2y(y-x)^4/15x3y^5(y-x)3 =4x^(-1)y^(-4)(y-x)/5 (2)4x2-4分之1-2x+x2 =(x-1)2/4(x+1)(x-1) =(x-1)/4(x+1) (3)x2+10x-24分之2x2-2x-4 =2(x2-x-2)/(x2+10x-24) =2(x-2)(x+1)/(x-2)(x+10) =2(x+1)/(x+...

①x2y2-5x2y-6x2 =x2(y2-5y-6)=x2(y-6)(y+1);②(p2+q2)2-4p2q2=(p2+q2+2pq)(p2+q2-2pq)=(p+q)2(p-q)2;③(a-b)4-3(a-b)2-10=[(a-b)2-5][(a-b)2+2]; ④x2-y2+4y-4=x2-(y2-4y+4)=x2-(y-2)2=(x+y-2)(x-y+2).

圆x²+y²-10x-10y=0 ==> (x²-10x+25)+(y²-10y+25)=50 ==> (x-5)²+(y-5)²=50 即,圆心O1(5,5),半径为5√2 元x²+y²-6x+2y-40=0 ==> (x²-6x+9)+(y²+2y+1)=50 ==> (x-3)²+(y+1)²=50 即...

Y1=(X+3)^2+1, Y2=-(X-2)^2-2, ∴A(-3,1),B(2,-2), 直线AB解析式Y=KX+b,得方程组: {1=-3K+b {-2=2K+b 解得:K=-3/5,b=-4/5, ∴直线AB:Y=-3/5X-4/5, 令Y=0,即-3/5X-4/5=0, X=-4/3, ∴m=-4/3。

联立方程,可得x2+y2?10x?10y=0x2+y2+6x+2y?40=0,解得x=?2y=6或x=4y=?2,∴两个圆的交点是A(-2,6),B(4,-2),∴|AB|=(4+2)2+(?2?6)2=10.

【解答】 ∵原式变形为(x-3)²+(y-1)²=0, ∴x=3,y=1 ∴矩形面积S=xy=3×1=3

z的法向量:(-2x,-2y,-1)平行于平面法向量(6,2,3),得p点(1,1/3,-1/9)再用距离公式d=1/3

第一个和第二个相减

设圆x2+y2-6x+5=0的圆心为C,则C的坐标是(3,0),由题意,CM⊥AB,①当直线CM与AB的斜率都存在时,即x≠3,x≠0时,则有kCMkAB=-1,∴yx?3×yx=?1(x≠3,x≠0),化简得x2+y2-3x=0(x≠3,x≠0),②当x=3时,y=0,点(3,0)适合题意,③当x=0时,y=0,...

(1)若m=5时,圆C1即:(x-3)2+(y+2)2 =4,圆C2:(x+5)2+(y+10)2=100,圆心距C1C2=82∈(8,12),∴两圆相交,交点个数为2个.(2)设点P的坐标为(x0,y0),圆C1与圆C2的半径分别为r1、r2,由题意得PC12?r12=PC22?r22,即 [(x0?3)2+(y0...

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